Blame view

kernel/linux-imx6_3.14.28/arch/c6x/lib/divremu.S 2.63 KB
6b13f685e   김민수   BSP 최초 추가
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
  ;;  Copyright 2011  Free Software Foundation, Inc.
  ;;  Contributed by Bernd Schmidt <bernds@codesourcery.com>.
  ;;
  ;; This program is free software; you can redistribute it and/or modify
  ;; it under the terms of the GNU General Public License as published by
  ;; the Free Software Foundation; either version 2 of the License, or
  ;; (at your option) any later version.
  ;;
  ;; This program is distributed in the hope that it will be useful,
  ;; but WITHOUT ANY WARRANTY; without even the implied warranty of
  ;; MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
  ;; GNU General Public License for more details.
  ;;
  ;; You should have received a copy of the GNU General Public License
  ;; along with this program; if not, write to the Free Software
  ;; Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
  
  #include <linux/linkage.h>
  
  	.text
  ENTRY(__c6xabi_divremu)
  	;; We use a series of up to 31 subc instructions.  First, we find
  	;; out how many leading zero bits there are in the divisor.  This
  	;; gives us both a shift count for aligning (shifting) the divisor
  	;; to the, and the number of times we have to execute subc.
  
  	;; At the end, we have both the remainder and most of the quotient
  	;; in A4.  The top bit of the quotient is computed first and is
  	;; placed in A2.
  
  	;; Return immediately if the dividend is zero.	Setting B4 to 1
  	;; is a trick to allow us to leave the following insns in the jump
  	;; delay slot without affecting the result.
  	mv	.s2x	A4, B1
  
    [b1]	lmbd	.l2	1, B4, B1
  ||[!b1] b	.s2	B3	; RETURN A
  ||[!b1] mvk	.d2	1, B4
  
  ||[!b1] zero	.s1	A5
  	mv	.l1x	B1, A6
  ||	shl	.s2	B4, B1, B4
  
  	;; The loop performs a maximum of 28 steps, so we do the
  	;; first 3 here.
  	cmpltu	.l1x	A4, B4, A2
    [!A2]	sub	.l1x	A4, B4, A4
  ||	shru	.s2	B4, 1, B4
  ||	xor	.s1	1, A2, A2
  
  	shl	.s1	A2, 31, A2
  || [b1]	subc	.l1x	A4,B4,A4
  || [b1]	add	.s2	-1, B1, B1
     [b1]	subc	.l1x	A4,B4,A4
  || [b1]	add	.s2	-1, B1, B1
  
  	;; RETURN A may happen here (note: must happen before the next branch)
  __divremu0:
  	cmpgt	.l2	B1, 7, B0
  || [b1]	subc	.l1x	A4,B4,A4
  || [b1]	add	.s2	-1, B1, B1
     [b1]	subc	.l1x	A4,B4,A4
  || [b1]	add	.s2	-1, B1, B1
  || [b0] b	.s1	__divremu0
     [b1]	subc	.l1x	A4,B4,A4
  || [b1]	add	.s2	-1, B1, B1
     [b1]	subc	.l1x	A4,B4,A4
  || [b1]	add	.s2	-1, B1, B1
     [b1]	subc	.l1x	A4,B4,A4
  || [b1]	add	.s2	-1, B1, B1
     [b1]	subc	.l1x	A4,B4,A4
  || [b1]	add	.s2	-1, B1, B1
     [b1]	subc	.l1x	A4,B4,A4
  || [b1]	add	.s2	-1, B1, B1
  	;; loop backwards branch happens here
  
  	ret	.s2	B3
  ||	mvk	.s1	32, A1
  	sub	.l1	A1, A6, A6
  ||	extu	.s1	A4, A6, A5
  	shl	.s1	A4, A6, A4
  	shru	.s1	A4, 1, A4
  ||	sub	.l1	A6, 1, A6
  	or	.l1	A2, A4, A4
  	shru	.s1	A4, A6, A4
  	nop
  ENDPROC(__c6xabi_divremu)