/* Copyright (C) 1992, 1997 Free Software Foundation, Inc.
     This file is part of the GNU C Library.
  
   * SPDX-License-Identifier:	LGPL-2.0+
   */
  
  typedef struct {
  	long    quot;
  	long    rem;
  } ldiv_t;
  /* Return the `ldiv_t' representation of NUMER over DENOM.  */
  ldiv_t
  ldiv (long int numer, long int denom)
  {
    ldiv_t result;
  
    result.quot = numer / denom;
    result.rem = numer % denom;
  
    /* The ANSI standard says that |QUOT| <= |NUMER / DENOM|, where
       NUMER / DENOM is to be computed in infinite precision.  In
       other words, we should always truncate the quotient towards
       zero, never -infinity.  Machine division and remainer may
       work either way when one or both of NUMER or DENOM is
       negative.  If only one is negative and QUOT has been
       truncated towards -infinity, REM will have the same sign as
       DENOM and the opposite sign of NUMER; if both are negative
       and QUOT has been truncated towards -infinity, REM will be
       positive (will have the opposite sign of NUMER).  These are
       considered `wrong'.  If both are NUM and DENOM are positive,
       RESULT will always be positive.  This all boils down to: if
       NUMER >= 0, but REM < 0, we got the wrong answer.  In that
       case, to get the right answer, add 1 to QUOT and subtract
       DENOM from REM.  */
  
    if (numer >= 0 && result.rem < 0)
      {
        ++result.quot;
        result.rem -= denom;
      }
  
    return result;
  }